Ex: 7.10 Java How to Program

Use a one-dimensional array to solve the following problem: A company pays its salespeople on a commission basis. The salespeople receive $200 per week plus 9% of their gross sales for that week. For example, a salesperson who grosses $5000 in sales in a week receives $200 plus 9% of $5000, or a total of $650. Write an applet (using an array of counters) that determines how many of the salespeople earned salaries in each of the following ranges (assume that each salesperson’s salary is truncated to an integer amount):

a) $200–299
b) $300–399
c) $400–499
d) $500–599
e) $600–699
f) $700–799
g) $800–899
h) $900–999
i) $1000 and over

import java.util.Scanner;

public class Sales {
 public static void main (String args[]){
  int [] total = new int [9];
 
  Scanner input = new Scanner (System.in);
  int range;  
  int salary = 200;
  double commission = .09; 
  
  while (input.hasNext()){
   
   double income  = salary + input.nextInt()*commission;
   range = (int)income / 100;
   if (range > 9 )
    range = 10;
   ++total [range -2];
  }
  
  
 System.out.println("Range \t \t Number"); 
  for (int i = 0 ; i < total.length-1; i++){
   System.out.printf("\n$"+(200+100*i) + "- $"+(299+100*i)+"\t \t"+total[i]+"\n");
  }
  System.out.println("$1000 and over \t \t"+total[total.length-1]); 
 }
}